Chemistry - CHEMICAL BONDING Question with Solution | TestHub
Assess statements (i)-(v), then select every correct description of their truth values.
(i) The ideal bond-angle order is H₂O < NH₃ < CH₄ < CO₂.
(ii) A tetrahedral complex molecule has no plane containing its centre and two ligands.
(iii) Superoxide is paramagnetic whereas peroxide is diamagnetic.
(iv) A nitrogen atom and an N₂ molecule must have identical first ionization energies because both contain nitrogen.
(v) Removing one electron from a bonding HOMO lowers bond order, whereas removing one from an antibonding HOMO raises it.
Options:(select one or more)
Answer:
Solution:
(i) The bond angle follows the order .
(ii) Any three non-collinear points define a plane, so this statement is false.
(iii) Superoxide (O₂⁻) has one unpaired * electron, while peroxide (O₂²⁻) has none. Therefore, this statement is true.
(iv) Atomic and molecular ionization depend on distinct orbital environments, which rejects this statement.
(v) The bond order (BO) is defined by the formula:
where is the number of electrons in bonding orbitals and is the number of electrons in antibonding orbitals.
Thus, the true statements are {i, iii, v}, and the false statements are {ii, iv}. This corresponds to selecting options A and B. It is important to note that an even total electron count does not, by itself, prove a closed shell.
