Select the INCORRECT combination.

Question

TestHub · Accepted Answer

Borax (Q) and Sodium Peroxoborate (P) contain ionic bonds between Na⁺ and their respective cyclic complex anions.

Sodium Peroxoborate (P) has no $π$ -bonds and forms a cyclic structure with B-O-O-B linkages.

Borax (Q) contains B-O-B (X-O-X) linkages, ionic bonds, and exactly two sp² hybridized boron atoms. Poly/Metaphosphate (S) has an even number of $π$ -bonds (for even $n$ ) and contains P-O-P linkages. Melamine (R), C₃N₃(NH₂)₃, contains a benzene-like ring with alternating single and double bonds.

It possesses exactly 3 $π$ -bonds, which is an odd number, making combination 1 ("even number of $π$ -bonds") incorrect.

Therefore, (D) R - 1 - (iv) is the INCORRECT combination.

Column-I (Compounds)	Column-II (Characteristics)	Column-III (Characteristics)
(P) $Na_{2} B_{2} O_{4} (OH)_{4}$	(1) Contains even number of $π$ -bonds	(i) Contains X-O-X linkage
(Q) $Na_{2} B_{4} O_{5} (OH)_{4}$	(2) Contains odd number of $π$ -bonds	(ii) Has cyclic structure
(R) $C_{3} N_{3} (NH_{2})_{3}$	(3) No $π$ -bonds are present	(iii) Has $\geq 2 sp^{2}$ hybridised atoms
(S) $Na_{6} [(PO_{3})_{6}]$	(4) Has ionic bond	(iv) Has $\leq 3 sp^{3}$ hybridised atoms

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