Chemistry - CHEMICAL BONDING Question with Solution | TestHub

Identify Paramagnetic Species ($X$): $\cdot$CH₃, $\cdot$ClO₃, O₂, and NO₂ have unpaired electrons, so $X=4$.

Identify Species with $\pi$ Bonds ($Y$): $\cdot$ClO₃, O₂, O₃, and NO₂ contain $\pi$ bonds, so $Y=4$.

Calculate the Excited State: The state is given by $\frac{X+Y}{2}=\frac{4+4}{2}=4^{t}h$ excited state.

Determine Principal Quantum Number ($n$): For Li²⁺, the ground state is $n=1$, so the $4^{t}h$ excited state corresponds to $n=5$.

Calculate Degenerate Orbitals: The number of degenerate orbitals in a single-electron species (Li²⁺) is $n^2=5^2=25$.