Chemistry - CHEMICAL BONDING Question with Solution | TestHub

ChemistryCHEMICAL BONDINGIntroduction, ValencyMedium2 minQB
ChemistryMediuminteger

(i) What is the oxidation of potassium ion in

(ii) Find the magnitude formal charge on the carbon atom in

(iii) Find formal charge as O in

For example if x is = 9, y = 8 and z = 6 then your answer is 986 for OMR

Answer:
111
Solution:

(i) Oxidation state of K in KO₂:

KO₂ is potassium superoxide.

O₂⁻ is superoxide ion, charge = –1.

K⁺ + O₂⁻ → Oxidation state of K = +1 → x = 1

(ii) Formal charge on carbon in CO:

CO Lewis structure: C≡O with lone pair on C and O

Formal charge formula: FC = valence – nonbonding – ½(bonding)

Carbon: 4 – 2 – 3 = –1 → magnitude = 1 → y = 1

(iii) Formal charge on oxygen in CO:

Oxygen: 6 – 2 – 3 = +1 → magnitude = 1 → z = 1

Stream:JEESubject:ChemistryTopic:CHEMICAL BONDINGSubtopic:Introduction, Valency
2mℹ️ Source: QB

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