A molecule A − B has a bond length of 1.6 A ˚ Å and dipole moment of 0.64 Debye. Find % covalent character in this molecule. [Electronic charge = 4.8 × 1 0 − 10 esu )

Question

TestHub · Accepted Answer

Concepts: Dipole moment, ionic character, covalent character.

Calculation:

$μ_{i o ni c} = q \times d = 4.8 \times 1 0^{- 10} es u \times 1.6 \times 1 0^{- 8} c m = 7.68 De b ye$

$% i o ni cc ha r a c t er = (\frac{0.64}{7.68}) \times 100 = 8.33%$

$% co v a l e n t c ha r a c t er = 100 - 8.33 = 91.67%$

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