X = Number of bonding electrons in O 2 molecules which have higher energy than -32.38 eV . Y = Number of antibonding electrons in O 2 molecules which have lower energy than –32.38 eV. Find ( X + Y

Question

X = Number of bonding electrons in O 2 ​ molecules which have higher energy than -32.38 eV . Y = Number of antibonding electrons in O 2 ​ molecules which have lower energy than –32.38 eV. Find ( X + Y ) .

TestHub · Accepted Answer

Question Explanation: Counting bonding and antibonding electrons relative to energy levels.

Concept: Molecular Orbital Energy Distribution.

Solution: In O₂, bonding orbitals formed from 2p orbitals $(σ 2 p_{z}, π 2 p_{x, y})$ have higher energy than the 2s level ( $- 32.38 e V$ ). Antibonding orbitals below this level involve the 1s shell.

Calculation:

X (Bonding $e^{-}$ > $- 32.38 e V$ ): $2 (σ 2 p_{z}) + 4 (π 2 p_{x, y}) = 6$

Y (Antibonding $e^{-}$ < $- 32.38 e V$ ): $2 (σ^{*} 1 s) = 2$

Total: $X + Y = 6 + 2 = 8$

Final Answer: 8.00

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