Chemistry - CHEMICAL BONDING Question with Solution | TestHub
The simplest boron hydride known is diborane (B₂H₆). As implied by the mechanism of hydrolysis, diborane and many other light boron hydrides act as Lewis acids, and they are cleaved by reaction with Lewis bases. Two different cleavage patterns have been observed: symmetric cleavage and unsymmetric cleavage.
In symmetric cleavage, B₂H₆ is broken symmetrically into two BH₃ fragments with NMe₃. While with NH₃, MeNH₂, MeNH₂ results in unsymmetrical cleavage, which is a cleavage leading to an ionic product.
Select the correct statement regarding .
(i) It is not a electron deficient compound
(ii) Maximum number of atoms in a plane are 6
(iii) type of overlapping is present
(iv) Bridge bond is longer than terminal bond
(v) Both the boron are hybridized
Answer:
Solution:
In B₂H₆, each boron atom is sp³ hybridized, making statement (v) correct. The structure contains 6 atoms in one plane (2 Boron and 4 terminal Hydrogen atoms), which confirms statement (ii). The two bridging Hydrogen atoms form 3-center 2-electron (3c-2e) bonds via overlapping, supporting statement (iii). These bridge bonds are longer () than terminal bonds (), making (iv) correct. Statement (i) is false because diborane is a well-known electron-deficient compound.