Chemistry - CHEMICAL BONDING Question with Solution | TestHub

The molecular species that exist as ion pairs in the solid state with non-planar cationic parts are:

$PC{l}_5(s)$: Dissociates into $[PC{l}_4{]}^{+}[PC{l}_6{]}^{-}$. The cation $[PC{l}_4{]}^{+}$ is tetrahedral (non-planar).

$PB{r}_5(s)$: Dissociates into $[PB{r}_4{]}^{+}B{r}^{-}$. The cation $[PB{r}_4{]}^{+}$ is tetrahedral (non-planar).

$Xe{F}_6(s)$: Dissociates into $[Xe{F}_5{]}^{+}{F}^{-}$. The cation $[Xe{F}_5{]}^{+}$ is square pyramidal (non-planar).

The remaining species ($N_2{O}_5$, $N_2{O}_4$, and $C{l}_2{O}_6$) form linear or bent cations ($[N{O}_2{]}^{+}$, $[NO{]}^{+}$, and $[Cl{O}_2{]}^{+}$), which are all planar. Therefore, the total number is 3.