Chemistry - CHEMICAL BONDING Question with Solution | TestHub

Option (A): The B atom in B₂H₆ and the Be atom in polymeric (BeH₂)ₙ both utilize four bridging/terminal bonds in a tetrahedral geometry, resulting in sp³ hybridization.

Option (B): The B in the borate anion is sp³ hybridized, while B in inorganic graphite (BN)ₓ forms a layered planar structure with sp² hybridization.

Option (C): The Al atom in Al(BH₄)₃ coordinates with 6 hydrogen atoms (sp³d²), whereas Be in Be(BH₄)₂ coordinates with 4 hydrogens (sp³).

Option (D): The Si atoms in cyclic silicate Si₆O₁₈¹²⁻ and S atoms in pyrosulfate S₂O₇²⁻ are both bonded tetrahedrally to 4 oxygen atoms, meaning both have sp³ hybridization.