Chemistry - CHEMICAL BONDING Question with Solution | TestHub

The electronic configuration of CN⁻ is

$({\sigma }_{1s}{)}^2({\sigma }_{1s}^{\ast }{)}^2({\sigma }_{2s}{)}^2({\sigma }_{2s}^{\ast }{)}^2({\pi }_{2p_y}{)}^2({\pi }_{2p_z}{)}^2({\sigma }_{2p_x}{)}^2$.

$B.O.=\frac{1}{2}(N_b-N_a)=\frac{1}{2}(10-4)=3$