Chemistry - CHEMICAL BONDING Question with Solution | TestHub

NO⁺ and CN⁻ both have 14 electrons and will both have the following configuration: $\sigma 1s^2{\sigma }^{\ast }1s^2\sigma 2s^2{\sigma }^{\ast }2s^2\left(\pi 2p_y^2=\pi 2p_z^2\right)\sigma 2p_x^2$.

Therefore, the bond order of NO⁺ = the bond order of CN⁻ = 3.