Chemistry - CHEMICAL BONDING Question with Solution | TestHub

ChemistryCHEMICAL BONDINGVSEPR, Bond Angle, Bond Length, Bond EnergyMedium2 minQB
ChemistryMediummatching list
Passage / Comprehension

Column-I

species

Column-II

Related to species of Column I

Column-III

Related to species of Column I & II

(P)

(1)

(i) square planar

(Q)

(2)

(ii) Hybridisation of central atom in cationic part is sp & anionic part is

 

(R) Carbon monoxide

(3) , total lone pair = 14

(iii) Gas at normal temp.

(S)

(4) Co-ordinate bond

(iv) Hybridisation of central atom in cationic part is & anionic part is

 

.

Which of the following matched is correct?

Options:

Answer:
B
Solution:

XeF₄ (Q): Central Xe has 4 bond pairs and 2 lone pairs, giving it an sp³d² hybridization and a square planar geometry (i). Lone Pairs: Total lone pairs = lone pairs, perfectly matching condition (3).

 

PCl₅(s) (P): Exists as , matching with (2) and (iv) where the cationic part is sp³ and the anionic part is sp³d².

 

N₂O₅(s) (S): Exists as , matching with (1) and (ii) where the cationic part is sp and the anionic part is sp².

Stream:JEESubject:ChemistryTopic:CHEMICAL BONDINGSubtopic:VSEPR, Bond Angle, Bond Length, Bond Energy
2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...