X = The number of species which have net zero dipole moment PC l 5 , S F 4 , H 2 O , S n C l 2 , C l 2 y = The number of isoelectronic species from the following having 14 electrons. M g 2 +

Question

X = The number of species which have net zero dipole moment PC l 5 ​ , S F 4 ​ , H 2 ​ O , S n C l 2 ​ , C l 2 ​ y = The number of isoelectronic species from the following having 14 electrons. M g 2 + , N a + , N 3 − , S 2 − , K + , C N − , N 2 ​ , N O + , P H 3 ​ , P + Find the value of 10x + y

TestHub · Accepted Answer

To find X, we analyze the dipole moments: PCl₅: Trigonal bipyramidal, nonpolar (X=1) SF₄: See-saw, polar H₂O: Bent, polar SnCl₂: Bent, polar Cl₂: Linear, nonpolar (X=2)

So, X = 2.

To find Y, we count 14-electron species: N³⁻ (7+3=10), S²⁻ (16+2=18), K⁺ (19-1=18), Mg²⁺ (12-2=10), Na⁺ (11-1=10) CN⁻ (6+7+1=14) (Y=1) N₂ (7+7=14) (Y=2) NO⁺ (7+8-1=14) (Y=3) PH₃ (15+3=18), P⁺ (15-1=14) (Y=4)

So, Y = 4.

Value = $10 X + Y = 10 (2) + 4 = 24$ .

Chemistry - CHEMICAL BONDING Question with Solution | TestHub

Doubts & Discussion