If the total number of sp 3 hybridised orbital of Al in dimer of AlCl 3 = X If the maximum number of atoms present in one plane of I 2 Cl 6 = Y then find the value of |Y–2X|.

Question

If the total number of sp 3 hybridised orbital of Al in dimer of AlCl 3 ​ = X If the maximum number of atoms present in one plane of I 2 Cl 6 = Y then find the value of |Y–2X|.

TestHub · Accepted Answer

In the dimer Al₂Cl₆, each of the two aluminum atoms is sp³ hybridized and contains four hybrid orbitals, giving $X = 2 \times 4 = 8$ .

In I₂Cl₆, each iodine atom is sp³d² hybridized with four bonding pairs and two lone pairs, making the entire molecule completely planar. Since it is planar, all atoms lie in the same plane, giving the maximum number of coplanar atoms as $Y = 2 (I) + 6 (Cl) = 8$ .

Substituting $X$ and $Y$ into the expression gives the final value: $∣ Y - 2 X ∣ = ∣8 - 16∣ = 8$ .

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