Chemistry - CHEMICAL BONDING Question with Solution | TestHub

To determine the bond order of the underlined species, NOHSO₄, we first need to identify the relevant bond. The question implies finding the bond order of the NO bond within the nitronium ion (NO⁺) which is part of the NOHSO₄ structure.

The NOHSO₄ compound contains the nitronium ion, NO⁺, and the bisulfate ion, HSO₄⁻. The bond order refers to the NO bond in the NO⁺ ion.

The NO⁺ ion has 10 valence electrons (5 from N, 6 from O, minus 1 for the positive charge).

The molecular orbital configuration is:

$({\sigma }_{2s}{)}^2({\sigma }_{2s}^{\ast }{)}^2({\sigma }_{2p}{)}^2({\pi }_{2p}{)}^4$

Bond order = $0.5\times (numberofelectronsinbondingorbitals-numberofelectronsinantibondingorbitals)$

Bond order = $0.5\times (8-2)=0.5\times 6=3$.

Therefore, the bond order of the NO bond in NOHSO₄ (specifically, the NO⁺ part) is 3.

The final answer is $\boxed{3}$.