Chemistry - CHEMICAL BONDING Question with Solution | TestHub

ChemistryCHEMICAL BONDINGMolecules do not exist, SilicatesMedium2 minQB

ChemistryMediumsingle choice

Passage / Comprehension

Column - I Anionic part of Silicate	Column- II Number of oxygen shared per tetrahedral	Column-III Types of Silicate
(I) $(Si_{4} O_{11}^{- 6})_{n}$	(i) 1	(P) Cyclic
(II) $(SiO_{3}^{- 2})_{n}$	(ii) 2	(Q) Amphibole
(III) $(Si_{2} O_{5}^{- 2})_{n}$	(iii) 2.5	(R) Sheet
(IV) $(SiO_{2})_{n}$	(iv) 3	(S) Pyroxene

Select the INCORRECT combination.

Answer:

Solution:

Anionic Part (I): $(S i_{4} O_{11})_{n}^{6 -}$ represents an amphibole (double chain silicate).

Oxygen Sharing (ii): Sharing $2$ oxygens per tetrahedron forms a cyclic or single chain silicate, not an amphibole.

Type of Silicate (R): Sheet silicates share $3$ oxygens per tetrahedron and have the formula $(S i_{2} O_{5})_{n}^{2 -}$ .

Amphibole Reality: Amphiboles actually share an average of $2.5$ oxygens per tetrahedron, making combination (I) (iii) (Q) the correct match.

Stream:JEESubject:ChemistryTopic:CHEMICAL BONDINGSubtopic:Molecules do not exist, Silicates

⏱ 2mℹ️ Source: QB

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