For HO–S(=O)₂–O–O–S(=O)₂–OH, use two lone pairs per oxygen. Let x be total σ bonds including O–H, a oxygen lone pairs, b oxygen atoms with tetrahedral electron-domain geometry in this contributor, and

Question

For HO–S(=O)₂–O–O–S(=O)₂–OH, use two lone pairs per oxygen. Let x be total σ bonds including O–H, a oxygen lone pairs, b oxygen atoms with tetrahedral electron-domain geometry in this contributor, and d formal π bonds. Find (x+a)/(b+d).

TestHub · Accepted Answer

x=8 S–O+1 O–O+2 O–H=11; a=8×2=16. Two OH and two peroxide O have four domains, so b=4; four terminal =O oxygens have three domains. d=4. Thus 27/8=3.375.

Chemistry - CHEMICAL BONDING Question with Solution | TestHub

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