Chemistry - CHEMICAL BONDING Question with Solution | TestHub

ChemistryCHEMICAL BONDINGMOTHard2 minQB
ChemistryHardmultiple choice

Consider C₂⁺, N₂⁺, O₂⁺ and F₂⁺, including1s electrons. Add one electron to each to make the neutral molecule. Use the standard s–p-mixed order for C, N and unmixed order for O, F. Select every starting ion for which the added electron enters a GERADE orbital AND the neutral product has at least six gerade electrons.

Options:(select one or more)

Answer:
B, C, D
Solution:

Carbon's added electron enters πᵤ, and neutral C₂ has 4 gerade electrons (σ₁ₛ²σ₂ₛ²). Nitrogen's enters σ, and neutral N₂ has 6 gerade electrons. Oxygen's and fluorine's enter π*, giving 8 and10 gerade electrons respectively in their neutral products. Thus B, C, D pass both tests. Counting all electrons instead of only the inversion-even orbitals would not distinguish these cases.

Stream:JEESubject:ChemistryTopic:CHEMICAL BONDINGSubtopic:MOT
⏱ 2mℹ️ Source: QB

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