Chemistry - CHEMICAL BONDING Question with Solution | TestHub

3 mole ${\mathrm{XeF}}_4$ on hydrolysis gives 2 mole ${\mathrm{XeO}}_3$ and 1 mole Xe

${\mathrm{XeO}}_3+{\mathrm{XeOF}}_4\to$ product(having see-saw shape)

with RbF , both ${\mathrm{XeF}}_4$ and ${\mathrm{XeF}}_6$ act as Lewis acid

with ${\mathrm{SbF}}_5$, both ${\mathrm{XeF}}_2$ and ${\mathrm{XeF}}_4$ act as Lewis base