Given below are two statements: Statement I: Aluminum upon reaction with NaOH forms [ A l ( O H ) 6 ] 3 − ion. Statement II: The geometry of I C l 4 − , Cl O 3 − , and I B r 2 − is square plan

Question

Given below are two statements:

Statement I: Aluminum upon reaction with NaOH forms $[A l (O H)_{6}]^{3 -}$ ion.

Statement II: The geometry of $I C l_{4}^{-}$ , $Cl O_{3}^{-}$ , and $I B r_{2}^{-}$ is square planar, pyramidal, and linear, respectively.

In the light of the above statements, choose the correct answer from the options given below:

TestHub · Accepted Answer

Statement I is false. Aluminum reacts with NaOH to form the tetrahydroxoaluminate(III) ion, $[A l (O H)_{4}]^{-}$ , not $[A l (O H)_{6}]^{3 -}$ .

Statement II is true. The geometries are: $I C l_{4}^{-}$ (square planar), $Cl O_{3}^{-}$ (pyramidal), and $I B r_{2}^{-}$ (linear).

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