Chemistry - CHEMICAL BONDING Question with Solution | TestHub

(A)   Bond length

Using bents rule : more electronegative atom takes more p-orbital characteristics.

So in case of O₂F₂ at one ‘O’ atom sp³ hybridization.

* P character is moving towards F but in case of OF₂ at only ‘O’ atom sp³ hybridization.

* P character is being distributed between two F more P character O₂F₂ > OF₂

* P character brings elongation in bond length

O–F bond length O₂F₂ > OF₂

(B) BCl₃ > BF₃

Due to back bonding in N(SiH₃ )₃ there is almost trigonal planar structure.

More lone pair in case of 

so more basic nature.

(C) is incorrect.

(D) BF₃ > BCl₃

Effect pπ-pπ back bonding in BF₃ 2pπ–2pπ

So more strength in case of BF₃ > BCl₃

Option (C) is incorrect.