If s and p-orbital mixing is operative for all species given, then how many of the following species are paramagnetic in nature?
O₂⁻, N₂, C₂, CN⁻, B₂, O₂²⁺

Question

If s and p-orbital mixing is operative for all species given, then how many of the following species are paramagnetic in nature? O₂⁻, N₂, C₂, CN⁻, B₂, O₂²⁺

TestHub · Accepted Answer

For species where s and p orbital mixing is considered, the MO energy order is:

$σ_{2 s} < σ_{2 s}^{*} < π_{2 p_{x}} = π_{2 p_{y}} < σ_{2 p_{z}}$

* O₂⁻ : 1 unpaired electron in $π_{2 p}^{*}$ → Paramagnetic

* N₂ : all electrons paired → Diamagnetic

* C₂ : all electrons paired → Diamagnetic

* CN⁻ : isoelectronic with N₂, all paired → Diamagnetic

* B₂ : 2 unpaired electrons in $π_{2 p}$ → Paramagnetic

* O₂²⁺ : all electrons paired → Diamagnetic

Total paramagnetic species = 2

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