Chemistry - CHEMICAL BONDING Question with Solution | TestHub

(1) S–X bond angle (X = F, Cl)

• O₂SF₂: F is smaller, higher electronegativity → lone pair-bond pair repulsion slightly larger → smaller bond angle
• O₂SCl₂: Cl is larger, bond pair repulsion slightly smaller → S–X angle larger
• Order: O₂SF₂ < O₂SCl₂

(2) O–S–O bond angle

• Lone pairs on S push O atoms → O₂SF₂: F smaller → O–S–O angle smaller
• O₂SCl₂: O–S–O angle larger
• Order: O₂SF₂ > O₂SCl₂

(3) Total number of lone pairs

• Both molecules: central S has 2 lone pairs → equal → option C

(4) S–X bond length

• S–F < S–Cl → O₂SF₂ < O₂SCl₂ → so O₂SF₂ > O₂SCl₂