Chemistry - CHEMICAL BONDING Question with Solution | TestHub

Electronic configuration of CN⁻, NO⁺, and CO is the same, i.e., $\sigma 1s^2{\sigma }^{\ast }1s^2\sigma 2s^2{\sigma }^{\ast }2s^2\pi 2p_y^2\pi 2p_z^2{\sigma }^{2}2px$.

$B.O.=\frac{1}{2}(N_b-N_a)$

$B.O.=\frac{1}{2}(10-4)=\frac{1}{2}(6)=3$ in each case.