If bonding in SF 6 is explained using only overlaping theory without considering hybridisation, then find maximum number of bonds which have same bond strength :

Question

If bonding in SF 6 ​ is explained using only overlaping theory without considering hybridisation, then find maximum number of bonds which have same bond strength :

TestHub · Accepted Answer

To explain bonding in SF₆ without hybridization, sulfur can use its 3s, 3p and 3d orbitals. Three S-F bonds can form from the overlap of sulfur's 3p orbitals with fluorine's 2p orbitals. These three bonds are mutually perpendicular and have identical bond strength. The remaining two S-F bonds would involve sulfur's 3d orbitals, which would have different overlap characteristics and thus different bond strengths.

And one will be formed with s orbital of S and p orbital of F.

Chemistry - CHEMICAL BONDING Question with Solution | TestHub

Doubts & Discussion