Chemistry - CHEMICAL BONDING Question with Solution | TestHub
ChemistryCHEMICAL BONDINGVSEPR, Bond Angle, Bond Length, Bond EnergyMedium2 minQB
ChemistryMediumnumerical
Find the number of molecules in which axial orbital length is higher than equatorial orbital length of central atom
PCl₅, PCl₃F₂, PF₄Cl, PCl₂F₃, PF₅
Answer:
5.00
Solution:
The molecules listed all have a trigonal bipyramidal (TBP) geometry. In TBP, axial bonds are longer than equatorial bonds due to greater repulsion from the three equatorial lone pairs/bond pairs. All five molecules (PCl₅, PCl₃F₂, PF₄Cl, PCl₂F₃, PF₅) exhibit this characteristic.
Stream:JEESubject:ChemistryTopic:CHEMICAL BONDINGSubtopic:VSEPR, Bond Angle, Bond Length, Bond Energy
⏱ 2mℹ️ Source: QB
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