Chemistry - CHEMICAL BONDING Question with Solution | TestHub

The ion $X{Y}^{-p}$ has 14 electrons and 3 fully filled sigma bonding orbitals. This implies it is a diatomic molecule.

For 14 electrons, the molecular orbital configuration is $({\sigma }_{1s}{)}^2({\sigma }_{1s}^{\ast }{)}^2({\sigma }_{2s}{)}^2({\sigma }_{2s}^{\ast }{)}^2({\sigma }_{2p_z}{)}^2({\pi }_{2p_x}{)}^2({\pi }_{2p_y}{)}^2$.

There are 5 sigma orbitals, but only 3 are bonding: ${\sigma }_{1s}$, ${\sigma }_{2s}$, ${\sigma }_{2p_z}$. All 3 are fully filled.

The ${\pi }_{2p_x}$ and ${\pi }_{2p_y}$ orbitals are also fully filled.

This configuration has no unpaired electrons, so the spin-only magnetic moment is 0 BM.

Since the magnetic moment is 0, the sum of spin-only magnetic moments for any possibilities of $X{Y}^{-p}$ will also be 0.