Chemistry - CHEMICAL BONDING Question with Solution | TestHub

${\mu }_R=\sqrt{{\mu }_1^2+{\mu }_2^2+2{\mu }_1{\mu }_2\cos 120^{\circ }}$

$={\sqrt{{\mu }_{}^{}}}^2$ (${\mu }_1={\mu }_2=\mu$)

$\mu ={\mu }_R=1.72$

${\mu }_R=\sqrt{{\mu }_1^2+{\mu }_2^2+2{\mu }_1{\mu }_2\cos 60^{\circ }}$

${\mu }_R=\sqrt{2{\mu }^2+2{\mu }^2(\frac{1}{2})}$ (${\mu }_1={\mu }_2=\mu$)

$\sqrt{3}\times {\mu }_{}$

$\sqrt{3}\times 1.72=2.98D$