A neutral cyclic oxide has formula S₄O₁₂ and consists of a ring of four sulfur atoms alternating with four bridging oxygens; each S also bears two terminal =O groups. Compare it with HO–S(=O)₂–O–O–S(=

Question

A neutral cyclic oxide has formula S₄O₁₂ and consists of a ring of four sulfur atoms alternating with four bridging oxygens; each S also bears two terminal =O groups. Compare it with HO–S(=O)₂–O–O–S(=O)₂–OH. Use a formal Lewis model with two lone pairs on each neutral oxygen. Which statements are correct?

TestHub · Accepted Answer

Each cyclic sulfur has two terminal and two bridging S–O σ bonds, so4×4=16; eight terminal double bonds give8π. Twelve oxygens have 24 lone pairs, excluding D. In the acid two oxygens are peroxide(−1), six are ordinary(−2), and two H are+1, so the sulfur sum is+12 and each equivalent S is+6. The written acid has one O–O bond and two OH groups. Counting a bridge once as a linkage but twice in the σ-bond total is essential.

Chemistry - CHEMICAL BONDING Question with Solution | TestHub

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