Consider the following statements - (i) NF 3

Question

Consider the following statements -

(i) $NF_{3} < NH_{3} < CH_{4} < CO_{2}$ (Bond angle)

(ii) $O - O < S - S < Se - Se < Te - Te$ (Bond Energy)

(iii) $B_{2} H_{6} = C_{2} H_{4} = Be_{2} H_{4}$ (maximum number of H atoms in a plane)

(iv) $AgF > AgCl > AgBr > AgI$ (solubility in water)

(v) $O_{2} < O_{2}^{-} < O_{2}^{2 -}$ (unpaired electron)

Select the appropriate option(s).

TestHub · Accepted Answer

(i) Bond angles: NF 3 ( 102. 5 ∘ ) < NH 3 ( 10 7 ∘ ) < CH 4 ( 109. 5 ∘ ) < CO 2 ( 18 0 ∘ ) . Correct. (ii) Bond energy: O − O ( 146 k J / m o l ) is lower than S − S ( 226 k J / m o l ) due to lone pair repulsion. The order is O − O < S − S > Se − Se > Te − Te . Incorrect. (iii) B 2 H 6 (4 H atoms in a plane), C 2 H 4 (6 H atoms in a plane), Be 2 H 4 (4 H atoms in a plane). Incorrect. (iv) Solubility of AgX in water: AgF > AgCl > AgBr > AgI . Correct. (v) Unpaired electrons: O 2 (2), O 2 − (1), O 2 2 − (0). Order is O 2 2 − < O 2 − < O 2 . Incorrect. Therefore, statements (i), (iii), and (iv) are correct. Statements (ii) and (v) are incorrect.

Chemistry - CHEMICAL BONDING Question with Solution | TestHub

Options:(select one or more)

Doubts & Discussion