Chemistry - CHEMICAL BONDING Question with Solution | TestHub

ChemistryCHEMICAL BONDINGBack bonding, Bridge bonding & odd electron moleculesMedium2 minQB
ChemistryMediuminteger

Consider the following molecules? (SiH₃)₃N, O(SiH₃)₂, PF₃, P(SiH₃)₃, OCl₂, CH₃–NCO, BCl₃ (i) if the total number of molecules in which all the atoms are in same plane (ii) if the total number of molecules in which back bonding is significantly present

(iii) if the total number of molecules in which all the atoms are not in same plane = R then find the value of ?

Answer:
1
Solution:

Planar Molecules (): OCl₂ and BCl₃ have all their atoms lying in a single plane.

Non-Planar Molecules (): (SiH₃)₃N, O(SiH₃)₂, PF₃, P(SiH₃)₃, and CH₃-NCO have atoms extending out of the plane due to tetrahedral -SiH₃/-CH₃ groups or pyramidal geometries.

pπ-dπ Back Bonding (): Significantly present in (SiH₃)₃N, O(SiH₃)₂, and PF₃ (where a lone pair from a 2p orbital is donated into an empty 3d orbital).

Substituting the values:

Stream:JEESubject:ChemistryTopic:CHEMICAL BONDINGSubtopic:Back bonding, Bridge bonding & odd electron molecules
2mℹ️ Source: QB

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