Chemistry - CHEMICAL BONDING Question with Solution | TestHub
Given below are two statements : Statement (I) : Among , exactly two of the species are paramagnetic and exactly two species has H.O.M.O as Antibonding Molecular orbital Statement (II) : Due to 2s-2p mixing in , the energy of pi bonding molecular orbital is lesser than sigma bonding molecular orbitals formed by overlapping of 2p orbitals of two N atoms. In the light of the above statements, choose the correct answer from the options given below :
Options:
Answer:
Solution:
Statement (I):
O₂⁺ (15 e⁻): Paramagnetic (1 unpaired e⁻), HOMO is (antibonding).
N₂²⁻ (16 e⁻): Diamagnetic, HOMO is (antibonding).
F₂ (18 e⁻): Diamagnetic, HOMO is (antibonding).
Thus, only O₂⁺ is paramagnetic. All three have HOMO as antibonding. So, Statement (I) is false.
Statement (II): Due to 2s-2p mixing in N₂, the energy of bonding MO is lower than bonding MO. This is a correct statement.
Therefore, Statement (I) is false but Statement (II) is true.