Find the number of overlapping strengths which are stronger than the 2 s − 2 p : 1 s − 1 s , 2 p − 2 p , 2 s − 3 p , 3 p − 3 p , 3 s − 3 p , 3 s − 3 s , 2 s − 2 s

Question

TestHub · Accepted Answer

Overlapping stronger than 2s–2p

Rule: Strength of overlap depends on closeness (lower n → stronger)

Compare with 2s–2p:

Stronger overlaps are:

1s–1s (very strong)

2p–2p (better directional overlap)

Others (3p, 3s etc.) are weaker due to larger size.

Count = 2

Answer = 2

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