Chemistry - CHEMICAL BONDING Question with Solution | TestHub

The atomic number of Ne is 10. The total number of electrons in Ne${}_2$ is 20. The molecular orbital electronic configuration of Ne${}_2$ is: ${{\sigma }_{1s}}^2{{{\sigma }^{\ast }}_{1s}}^2{{\sigma }_{2s}}^2{{{\sigma }^{\ast }}_{2s}}^2{{\sigma }_{2p_z}}^2{{\pi }_{2p_x}}^2{{\pi }_{2p_y}}^2{{{\pi }^{\ast }}_{2p_x}}^2{{{\pi }^{\ast }}_{2p_y}}^2{{{\sigma }^{\ast }}_{2p_z}}^2$ The highest occupied molecular orbital is ${\sigma }_{2p}^{\ast }$. Answer: ${\sigma }_{2p}^{\ast }$