Chemistry - CHEMICAL BONDING Question with Solution | TestHub

Given,

 $$\begin{gathered} \mathrm{\mu }=1.2\mathrm{D} \\ \mathrm{\mu }=\mathrm{q}\times \mathrm{d} \\ \text{where}, \mathrm{\mu } = \text{dipole moment} \\ \mathrm{q} = \text{charge} \\ \mathrm{d}= \text{distance} \end{gathered}$$

$\mathrm{q}= \frac{1.2 \mathrm{D}}{1.0{\mathrm{A}}^0}$

$\therefore \mathrm{q}=1.2\times {10}^{-10} \mathrm{esu}$

Hence, the charge present on each atom is approximately zero.