Chemistry - CHEMICAL BONDING Question with Solution | TestHub

$\begin{array}{rl}& {\mathrm{C}}_2\\ & \left(12{\mathrm{e}}^{-}\right):\sigma 1{\mathrm{s}}^2,{\sigma }^{\ast }1{\mathrm{s}}^2,\sigma 2{\mathrm{s}}^2,{\sigma }^{\ast }2{\mathrm{s}}^2\left[\pi 2{\mathrm{p}}_{\mathrm{x}}^2=\pi 2{\mathrm{p}}_{\mathrm{y}}^2\right]\\ & \text{ B.O. }=\frac{8-4}{2}=2\\ & {\mathrm{O}}_2\\ & \left(16{\mathrm{e}}^{-}\right):\sigma 1{\mathrm{s}}^2,{\sigma }^{\ast }1{\mathrm{s}}^2,\sigma 2{\mathrm{s}}^2,{\sigma }^{\ast }2{\mathrm{s}}^2,\sigma 2{\mathrm{pz}}^2\\ & \left[\pi 2{\mathrm{p}}_{\mathrm{x}}^2=\pi 2{\mathrm{p}}_{\mathrm{y}}^2\right]\left[\pi \ast 2{\mathrm{p}}_{\mathrm{x}}^1=\pi \ast 2{\mathrm{p}}_{\mathrm{y}}^1\right]\\ & \text{ B.O. }=\frac{10-6}{2}=2\\ & \text{ Be }{}_2\\ & \left(8{\mathrm{e}}^{-}\right):\sigma 1{\mathrm{s}}^2,{\sigma }^{\ast }1{\mathrm{s}}^2,\sigma 2{\mathrm{s}}^2,{\sigma }^{\ast }2{\mathrm{s}}^2\\ & \text{ B.O. }=\frac{4-4}{2}=0\\ & {\mathrm{Li}}_2\\ & \left(6{\mathrm{e}}^{-}\right):\sigma 1{\mathrm{s}}^2,{\sigma }^{\ast }1{\mathrm{s}}^2,\sigma 2{\mathrm{s}}^2\end{array}$ $\begin{array}{rl}& \text{ B.O. }=\frac{4-2}{2}=1\\ & {\mathrm{Ne}}_2\\ & \left(20{\mathrm{e}}^{-}\right):\sigma 1{\mathrm{s}}^2,{\sigma }^{\ast }1{\mathrm{s}}^2,\sigma 2{\mathrm{s}}^2,{\sigma }^{\ast }2{\mathrm{s}}^2,\sigma 2{\mathrm{pz}}^2\\ & \left[\pi 2{\mathrm{p}}_{\mathrm{x}}^2=\pi 2{\mathrm{p}}_{\mathrm{y}}^2\right]\left[\pi \ast 2{\mathrm{p}}_{\mathrm{x}}^2={\pi }^{\ast }2{\mathrm{p}}_{\mathrm{y}}^2\right]{\sigma }^{\ast }2{\mathrm{p}}_{\mathrm{z}}^2\\ & \text{ B.O. }=\frac{10-10}{2}=0\\ & {\mathrm{N}}_2\\ & \left(14{\mathrm{e}}^{-}\right):\sigma 1{\mathrm{s}}^2,{\sigma }^{\ast }1{\mathrm{s}}^2,\sigma 2{\mathrm{s}}^2,{\sigma }^{\ast }2{\mathrm{s}}^2\left[\pi 2{\mathrm{p}}_{\mathrm{x}}^2=\pi 2{\mathrm{p}}_{\mathrm{y}}^2\right]\sigma 2{\mathrm{p}}_{\mathrm{z}}^2\\ & \text{ B.O. }=\frac{10-4}{2}=6\\ & {\mathrm{He}}_2\\ & \left(4{\mathrm{e}}^{-}\right):\sigma 1{\mathrm{s}}^2,{\sigma }^{\ast }1{\mathrm{s}}^2\\ & \text{ B.O. }=\frac{2-2}{2}=0\end{array}$