If N a + ion is larger than M g 2 + ion and S 2 - is larger than C l - ion, which of the following will be least soluble in water?

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Higher the lattice energy lower the solubility. Out of the four combinations possible, the lattice energy of MgS (bi-bivalent ionic solid) is higher than those of $N a_{2} S, M g C l_{2}$ (uni-bivalent or biuni-valent ionic solids ) and NaCl (univalent ionic solids) and hence, MgS is the least soluble. Thus, due to higher charge/ion, the lattice formed between Mg²⁺and S^2-is very strong.
As lattice energy overweighs the hydration energy here, the salt is least soluble.

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