Chemistry - CHEMICAL BONDING Question with Solution | TestHub

(i)${\text{PH}}_5$does not exist because the electronegativity of H & P are almost same they should have${\text{sp}}^3\text{d}$hybridised but the H cannot distort the d orbital of P hence it is not exist while${\text{BiCl}}_5$${\text{Bi}}^{+3}$is more stable than${\text{Bi}}^{+3}$due to inert inert pair effect and in${\text{BiCl}}_5$steric crowding also present so it does not exist.

(ii)$\text{S}=1{\text{s}}^{2}2{\text{s}}^{2}2{\text{p}}^{6}3{\text{s}}^{2}3{\text{p}}^{4}3{\text{d}}^0$

In exicited state
p & d orbital of sulphur & p orbital of oxygen involved in$\text{π}$bond so${\text{SO}}_2$has$\text{pπ}-\text{dπ}$bond

(iii)${\text{I}}_3^{+}$

$\mathrm{2b}\text{p}+\mathrm{2l}\text{p}={\text{sp}}^3\text{hybridisation}$

(iv)${\text{SeF}}_4\& {\text{CH}}_4$