Chemistry - CHEMICAL BONDING Question with Solution | TestHub

In$\text{S}\text{i}\text{C}{\text{l}}_4$there is$\text{s}{\text{p}}^3$hybridisation so the structure is tetrahedral. In$\text{S}{\text{O}}_4^{2-},\text{P}{\text{O}}_4^{3-},\text{N}{\text{H}}_4^{+}$the structure is tetrahedral because in all hybridization is$\text{s}{\text{p}}^3.$But in$\text{S}\text{C}{\text{l}}_4,\text{s}{\text{p}}^3\text{d}$hydridisation is present so shape is different which is see saw.