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Chemistry - CHEMICAL BONDING Question with Solution | TestHub

ChemistryCHEMICAL BONDINGVSEPR, Bond Angle, Bond Length, Bond EnergyEasy2 minPYQ_2020

ChemistryEasysingle choice

The bond angle of $H_{2} Se$ is best described as

Options:

Answer:

Solution:

According to Drago's rule :

$∠ HXH : \underset{(10 4^{o})}{H_{2} O} > \underset{(9 2^{o})}{H_{2} S} > \underset{(9 1^{o})}{H_{2} Se} > \underset{(89 \cdot 5^{o})}{H_{2} Te}$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:CHEMICAL BONDINGSubtopic:VSEPR, Bond Angle, Bond Length, Bond Energy

⏱ 2mℹ️ Source: PYQ_2020

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