Chemistry - CHEMICAL BONDING Question with Solution | TestHub

Hybridisation also for$\underset{(\text{s}{\text{p}}^3)}{\ddot{\text{N}}{\text{H}}_3}$and$\underset{(\text{s}{\text{p}}^3)}{\text{N}{\text{H}}_4^{+}}$
${\text{AlH}}_3\left({\text{sp}}^{\text{2}}\right)\text{change}\text{to}{\text{NH}}_4^{-}\left({\text{sp}}^{\text{3}}\right)$
$\underset{{\text{sp}}^{\text{3}}}{{\text{NH}}_{\text{3}}}{\text{+H}}^{+}\to \underset{{\text{sp}}^{\text{3}}}{{\text{NH}}_{\text{4}}^{\text{+}}}$