Chemistry - CHEMICAL BONDING Question with Solution | TestHub

$–\mathrm{O}\mathrm{H}$Group and$–\mathrm{S}–\mathrm{H}$group have not linear geometries so they cannot cancel each other and net dipole moment is positive. Hence III and IV polar, in I and II$\mathrm{\mu }$cancel each other so${\mathrm{\mu }}_{\mathrm{n}\mathrm{e}\mathrm{t}}$is zero and they are non-polar.