Chemistry - CHEMICAL BONDING Question with Solution | TestHub

In$\mathrm{B}{\mathrm{F}}_3$there is p$\mathrm{\pi }$-$\mathrm{p}\mathrm{\pi }$type of back bonding while in$(\mathrm{S}\mathrm{i}{\mathrm{H}}_3{)}_3\mathrm{N}$there is p$\mathrm{\pi }$-$\mathrm{d}\mathrm{\pi }$type of back bonding.
Here ammonia does not show back bonding.