Chemistry - CHEMICAL BONDING Question with Solution | TestHub

Here hybridisation changes from$\mathrm{s}{\mathrm{p}}^2$to$\mathrm{s}{\mathrm{p}}^3$when${\mathrm{H}}_3\mathrm{B}{\mathrm{O}}_3$combines with$\mathrm{O}{\mathrm{H}}^{-}$
$\underset{\mathrm{s}{\mathrm{p}}^2}{{\mathrm{H}}_3\mathrm{B}{\mathrm{O}}_3}+\mathrm{O}{\mathrm{H}}^{-}\to \underset{\mathrm{s}{\mathrm{p}}^3}{\left[\mathrm{B}\right(\mathrm{O}\mathrm{H}{)}_4{]}^{-}}$
In rest other reactions hybridisation does not change
$\underset{\mathrm{s}{\mathrm{p}}^3}{\stackrel{.\mathrm{}.}{\mathrm{N}}{\mathrm{H}}_3}+{\mathrm{H}}^{+}\to \underset{\mathrm{s}{\mathrm{p}}^3}{\mathrm{N}{\mathrm{H}}_4^{+}}$
$\underset{\mathrm{s}{\mathrm{p}}^3}{2\mathrm{N}{\mathrm{H}}_3}\rightleftharpoons \underset{\mathrm{s}{\mathrm{p}}^3}{2\mathrm{N}{\mathrm{H}}_2^{-}}+\underset{\mathrm{s}{\mathrm{p}}^3}{\mathrm{N}{\mathrm{H}}_4^{+}}$
$\underset{\mathrm{s}{\mathrm{p}}^3}{{\mathrm{H}}_2\mathrm{O}}+{\mathrm{H}}^{+}\rightleftharpoons \underset{\mathrm{s}{\mathrm{p}}^3}{{\mathrm{H}}_3{\mathrm{O}}^{+}}$