The number of compounds having all atoms in a single plane are

$X e F_{4}$ , $S F_{4}$ , $A l_{2} C l_{6}$ , $S n C l_{4}$ , $I_{2} C l_{6}$ , $H_{2} C = C = C = C H_{2}$ , $P h C l, C_{2} (C N)_{4}$ , $I C l_{3}$ , $P C l_{5}$

Question

The number of compounds having all atoms in a single plane are X e F 4 , S F 4 , A l 2 C l 6 , S n C l 4 , I 2 C l 6 , H 2 C = C = C = C H 2 , P h C l , C 2 ( C N ) 4 , I C l 3 , P C l 5

TestHub · Accepted Answer

Sol. X e F 4 - square planar, S F 4 - seesaw, A l 2 C l 6 - tetrahedral at aluminium, S n C l 4 - tetrahedral, I 2 C l 6 -planar dimer, H 2 C = C = C = C H 2 -terminal hydrogens in one plane, PhCl-planar molecules, C 2 ( C N ) 4 - trigonal planar at carbon, I C l 3 - T-shaped, P C l 5 - trigonal pyramidal. Here, XeF 4 , I 2 Cl 6 , H 2 C = C = CH 2 , Ph − Cl , C 2 CN 4 , ICl 3 are planar

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