Chemistry - CHEMICAL BONDING Question with Solution | TestHub

At Para positions$\overrightarrow{\mathrm{\mu }}$values cancel each other
So, net dipole moment is due to ortho positions$\overrightarrow{\mathrm{\mu }}$
$\mathrm{\mu }=\sqrt{{\mathrm{\mu }}^2+{\mathrm{\mu }}^2+2{\mathrm{\mu }}^2\text{cos 120}}$
$\text{μ}\text{=}\text{1}\text{.5 D}$