Chemistry - CHEMICAL BONDING Question with Solution | TestHub

$\mathrm{U}{\mathrm{F}}_6$has essentially covalent character. This is because small highly charged cations polarise the anions more effectively. For a metal with variable oxidation states, the halide with higher oxidation state of metal will be more covalent than the halide with lower oxidation of the metal. For example,$\mathrm{P}\mathrm{b}\mathrm{C}{\mathrm{l}}_4,\mathrm{S}\mathrm{n}\mathrm{C}{\mathrm{l}}_4$and$\mathrm{U}{\mathrm{F}}_6$are more covalent in nature than$\mathrm{P}\mathrm{b}\mathrm{C}{\mathrm{l}}_2,\mathrm{S}\mathrm{n}\mathrm{C}{\mathrm{l}}_2$and$\mathrm{U}{\mathrm{F}}_4$respectively.