For the following pattern of hybridization shown by the central atom,
$\begin{matrix} sp, & {sp}^{2}, & {sp}^{3} \\ (1) & (2) & (3) \end{matrix} \begin{matrix} {sp}^{3} d \\ (4) \end{matrix}$
which of the following options represent the correct sequence of hybridisation, i.e. according to the sequence mentioned above?

Question

TestHub · Accepted Answer

The orbitals of the central atom that goes for hybridization are:

$(a)$ Orbitals used for a $σ$ bond formation

$(b)$ Orbitals that contain $l p$ (lone pair) of electrons

$(c)$ If required empty orbitals

Note:Orbitals involved in $π$ -bond formation and having odd electron will not get hybrid.

Thus,

Molecule	Hybridisation	Number of $σ$ bonds $+ l p$
$C O_{2}$	$s p$	(number of $σ$ bonds $= 0$ number of $l p$ of electrons $= 0$ )
$B F_{3}$	$s p^{2}$	(number of $σ$ bonds $= 3$ number of $l p$ of electrons $= 0$ )
$H_{2} O$	$s p^{3}$	(number of $σ$ bonds $= 2$ number of $l p$ of electrons $= 2$ )
$P C l_{5}$	$s p^{3} d$	(number of $σ$ bonds $= 5$ number of $l p$ of electrons $= 0$ )

Chemistry - CHEMICAL BONDING Question with Solution | TestHub

Options:

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