Chemistry - CHEMICAL BONDING Question with Solution | TestHub

Hybridisation of Xe$\to \mathrm{s}{\mathrm{p}}^3{\mathrm{d}}^2$
All four$\mathrm{X}\mathrm{e}-\mathrm{F}$bonds are of equal lengths as they lie in the same plane and are at$90°$apart from each other.

Hybridisation$\to \mathrm{s}{\mathrm{p}}^3\mathrm{d}$
$\underset{\left(1.58\mathrm{\AA }\right)}{(\mathrm{P}-\mathrm{F}{)}_{\mathrm{a}\mathrm{x}\mathrm{i}\mathrm{a}\mathrm{l}}>}\underset{\left(1.53\mathrm{\AA }\right)}{(\mathrm{P}-\mathrm{F}{)}_{\mathrm{e}\mathrm{q}\mathrm{u}\mathrm{a}\mathrm{t}\mathrm{o}\mathrm{r}\mathrm{i}\mathrm{a}\mathrm{l}}}$

Hybridisation$\to \mathrm{s}{\mathrm{p}}^3\mathrm{d}$
$(\mathrm{S}-\mathrm{F}{)}_{\mathrm{a}\mathrm{x}\mathrm{i}\mathrm{a}\mathrm{l}}>(\mathrm{S}-\mathrm{F}{)}_{\mathrm{e}\mathrm{q}\mathrm{u}\mathrm{a}\mathrm{t}\mathrm{o}\mathrm{r}\mathrm{i}\mathrm{a}\mathrm{l}}$