The sum of the number of lone pairs of electrons on each central atom in the following species is

$[T e B r_{6}]^{2 -}, [B r F_{2}]^{+}$ and $[X e F_{3}]^{-}$

(Atomic number: F = 9, Br = 35, Te = 52, Xe = 54)

Question

The sum of the number of lone pairs of electrons on each central atom in the following species is [ T e B r 6 ] 2 - , [ B r F 2 ] + and [ X e F 3 ] - (Atomic number: F = 9, Br = 35, Te = 52, Xe = 54)

TestHub · Accepted Answer

Species Lone pair on central atom T e B r 2 - 1 B r F 2 + 2 X e F 3 - 3 Total number of lone pair = 6.

Species	Lone pair on central atom
$T e B r^{2 -}$	1
$B r F_{2}^{+}$	2
$X e F_{3}^{-}$	3

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